Hey Dave... the size of the Smart, the available space for big amps to drive big woofers suggest that your size and power needs to enjoy the same sound stage loudness and quality will not require more then the stock system can deliver
A 90 Amp rated alternator only can deliver that amount of amps at it's highest expected RPM and very cold temperatures. As rpm is reduced and temperature is raised the real output is DRAMATICALLY reduced in every automotive alternator ever made...
So practically speaking this is a typical system and at normal operating temp 180~200F and at cruise speed of 70mph motor rpm is 3250 and alt rpm is in the 5000~6000 range... the heat de rating means you should see about 65~70 amp max output
At night with high-beams on, heater motor or A/C blowing and all systems energized (fuel pump, black boxes etc) the engineers sized the battery and alt to have 20%~40% overhead... lets assume (becaus none of us know yet) that there is 35amps of normal operation draw from the 65~70 available
The only time amp draw exceeds system design power is starting. During starting about 100~300 amps are demanded from the battery before the alt energizes and then it must replenish the battery...
The typical voltage regulator will allow up to 14.7~8vdc to recharge the bat and should fall back to 13.8 to 14.2 most of the time.... your higher draw from the stereo amp will be sensed and the regulator should increase back to 14.7 vdc
Only you know the max constant watts or amp draw from the system you are thinking...
I personally think if you want good clean sound it can be done with low amp draw....and well within the available power...
Do you know ohms law and how to compute how many amps you need from the watts rating of your amp?
Watts (power) = volts X current (amps)
or said another way Watts / Volts = Amps
To calculate the current draw of an amplifier, multiply the number of channels by the RMS watts per channel (a 4 channel amp rated at 100 watts RMS per channel would be 400 watts). Double it to account for amplifier inefficiency fo 50% (400 watts X 2 = 800 watts), then divide by the average output Voltage of an alternator, 13.8 volts (800 divided by 13.8 = 58 amps). Since the average music signal requires about 1/3rd of the average power in a test tone, divide by 3 (58 amps divided by 3 = 19 amps). The result is the amplifier's approximate average current draw. In short, a 400 watt class A/B amplifier draws about 19 amps when playing music!
Most people use a class D amplifier for their subwoofers, which are somewhere around 90% efficient, not the 50% figure I used for the class A/B amplifiers in the example above. So a 1000 watt class D subwoofer amplifier draws about 1100 watts at full power (rarely, if ever happens), and would draw somewhere around 27 amps while playing music. That's about 46 amps (19+27) of current draw while playing music - pretty loud. Again, since music is DYNAMIC, these numbers aren't constant, and will be lower most of the time, giving the alternator a chance to charge the battery!
Now..... if you are one of those nice young men running around town sharing only the bass thump with the rest of us two blocks away...well then I hope your alt melts down fast...really... it annoys me to not get to hear all the instruments and vocals...grin
Don't ask me about stiffinging caps... if you size the system and feed lines properly there is no need for 1, 2, or 5 Fahrad capacitors!
Here is some very good info and a great web site for car audio stuff
http://www.the12volt.com/installbay/...TID=73496&PN=1